(5x+6)(x^2+3x-4)=0

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Solution for (5x+6)(x^2+3x-4)=0 equation:


Simplifying
(5x + 6)(x2 + 3x + -4) = 0

Reorder the terms:
(6 + 5x)(x2 + 3x + -4) = 0

Reorder the terms:
(6 + 5x)(-4 + 3x + x2) = 0

Multiply (6 + 5x) * (-4 + 3x + x2)
(6(-4 + 3x + x2) + 5x * (-4 + 3x + x2)) = 0
((-4 * 6 + 3x * 6 + x2 * 6) + 5x * (-4 + 3x + x2)) = 0
((-24 + 18x + 6x2) + 5x * (-4 + 3x + x2)) = 0
(-24 + 18x + 6x2 + (-4 * 5x + 3x * 5x + x2 * 5x)) = 0
(-24 + 18x + 6x2 + (-20x + 15x2 + 5x3)) = 0

Reorder the terms:
(-24 + 18x + -20x + 6x2 + 15x2 + 5x3) = 0

Combine like terms: 18x + -20x = -2x
(-24 + -2x + 6x2 + 15x2 + 5x3) = 0

Combine like terms: 6x2 + 15x2 = 21x2
(-24 + -2x + 21x2 + 5x3) = 0

Solving
-24 + -2x + 21x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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